Add Client.SendIQ method

disco_info_form
Wichert Akkerman 5 years ago committed by Mickaël Rémond
parent 070934743f
commit 8088e3fa7e

@ -1,6 +1,7 @@
package xmpp
import (
"context"
"encoding/xml"
"errors"
"fmt"
@ -82,6 +83,8 @@ func (em EventManager) streamError(error, desc string) {
// Client
// ============================================================================
var ErrCanOnlySendGetOrSetIq = errors.New("SendIQ can only send get and set IQ stanzas")
// Client is the main structure used to connect as a client on an XMPP
// server.
type Client struct {
@ -221,6 +224,27 @@ func (c *Client) Send(packet stanza.Packet) error {
return c.sendWithWriter(c.transport, data)
}
// SendIQ sends an IQ set or get stanza to the server. If a result is received
// the provided handler function will automatically be called.
//
// The provided context should have a timeout to prevent the client from waiting
// forever for an IQ result. For example:
//
// ctx, _ := context.WithTimeout(context.Background(), 30 * time.Second)
// client.SendIQ(ctx, iq, func(s Sender, p stanza.Packet) {
// // Handle the result here
// })
//
func (c *Client) SendIQ(ctx context.Context, iq stanza.IQ, handler HandlerFunc) (*IqResultRoute, error) {
if iq.Attrs.Type != "set" && iq.Attrs.Type != "get" {
return nil, ErrCanOnlySendGetOrSetIq
}
if err := c.Send(iq); err != nil {
return nil, err
}
return c.router.NewIqResultRoute(ctx, iq.Attrs.Id).HandlerFunc(handler), nil
}
// SendRaw sends an XMPP stanza as a string to the server.
// It can be invalid XML or XMPP content. In that case, the server will
// disconnect the client. It is up to the user of this method to

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